f(x) =3x+2 g(x) =4x-5 maka g^-1of^-1=??
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f(x) = 3x + 2
f^-1(x) = (x-2)/3
g(x) = 4x - 5
g^-1(x) = (x+5)/4
(g^-1 o f^-1)(x) = g^-1(f^-1(x))
g^-1((x-2)/3) = [(x-2)/3 + 5]/4
= (x/3 - 2/3 + 5)/4
= x/12 - 2/12 + 5/4
= (x-2)/12 + 15/12
= (x-2+15)/12
= (x+13)/12
Jadi, (g^-1 o f^-1) = (x+13)/12
[answer.2.content]
